Suppose a parabola has a vertex (4,7) and also passes through the point (3,8) Write the equation of the parabola in vertex form f(x)=a(xh)^2k I believe h=4 k=7 Not sure what to do from here MathFrom this chart, we see that the parabola y = x 2 contains the points (3, 9) and (4, 16) On the other hand, he parabola y = 2x 2 contains the points (3, 18) and (4, 32) On the first equation, y = x 2, to move horizontally across the xaxis from x = 3 to x = 4, we move up vertically on the yaxis from y = 9 to y = 16 which is 7 unitsSo, to go from the point (3, 9) to (4, 16), we move over 1See the answer See the answer See the answer done loading

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Y=x^2 2x-8 in vertex form
Y=x^2 2x-8 in vertex form-Y = x2 − 2x − 8 y = x 2 2 x 8 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 2 x − 8 x 2 2 x 8 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 2, c = − 8 a = 1, b = 2, c = 8 Consider the vertex form of a parabolaTo find the vertex form of the parabola, we use the concept completing the square method Vertex form of a quadratic function y = a(x h) 2 k In order to find the maximum or minimum value of quadratic function, we have to convert the given quadratic equation in the above form




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Vertex form is y = 2 (x 6)^2 – 13 Standard form of given equation is y = 2 x^2 24 x 59 Where, Characteristic Points are Vertex P (6, 13) Yintercept P (0, 59) An online parabola vertex calculator can display a parabola graph with exact values when you substitute the same values for a vertex form equation5 hours ago Substitute (3, 8) for ( x, y) in the vertex form to find a The function of the parabola is 62/87,21 From the figure, the vertex ( h, k) of the parabola is (±3, 2) Substitute ( ±1, 8) for ( x, y) in the vertex form to find a The function of the parabola is Write each function inGive the vertex of each function, and graph it How does vertex form compare to the other forms in each problem?
10) Use your calculator to find the vertex, xintercepts, and yintercept Do they match yours?Question Write y=2x^212x14 in vertex form Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website! Explanation Changing a quadratic function from standard form to vertex form actually requires that we go through the process of completing the square To do this, we need the x2 and x terms only on the right side of the equation y = x2 2x −8 y 8 = x2 2x −8 8 y 8 = x2 2x −8 8 y 8 = x2 2x
11) y = (x 3)2 2 12) y = (x 4)2 13) y = x2 3 14) y = x2 3 Convert each function to standard form Give the vertex and yinterceptThe ycoordinate of the vertex is $$ y = f(1) = 1^22\cdot12 = 1 2 2 = 1 $$ The yintercept is $$ y = f(0) = 0^22\cdot02 = 0 0 2 = 2 $$ In this case xintercept doesn't exist since equation $x^22x2=0$ does not has the solutions (use quadratic equation solver to check ) So, in this case we will plot the graph using onlySection 111 Graphs and Vertex Form In this section, we will explore quadratic functions and, in particular, their vertex and factored forms Example 1111 Maia has a remotecontrolled airplane and she is going to do a stunt dive where the plane dives



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Example 13 Rewrite in y = a (x − h) 2 k form and determine the vertex y = 2 x 2 − 4 x 8 Solution Since a = 2, factor this out of the first two terms in order to complete the square Leave room inside the parentheses to add a constant termY = a (xh)^2 k is the vertex form equation Now expand the square and simplify You should get y = a (x^2 2hx h^2) k Multiply by the coefficient of a and get y = ax^2 2ahx ah^2 k This is standard form of a quadratic equation, with the normal a, b and c in ax^2 bx c equaling a, 2ah and ah^2 k, respectivelyIn this section, we will explore quadratic functions using graphing technology and learn the vertex and factored forms of a quadratic function's formula




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Subtract 3 from both sides x^ {2}2x=y3 Multiply 2 and 1 to get 2 x^ {2}2x1=y31 Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=y2 AddSubtract y from both sides Subtract y from both sides x^ {2}2x1y=0 x 2 2 x 1 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2 for b, and 1y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation isOur perfect square trinomial factors into two identical binomials, (x6)•(x6) The vertex of an equation in vertex form




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But the equation for a parabola can also be written in "vertex form" y = a(x ?Regents Exam Questions FIFC8 Vertex Form of a Quadratic Name _____ wwwjmaporg 1 FIFC8 Vertex Form of a Quadratic 1 In the 8 Determine and state the vertex of f(x) =x2 −2x−8 using the method of completing the square 9 Use the method of completing the square to determine the vertex of f(x) =x2 −14x−15 State y 9/8 = 2(x 2 3/2 x 9/16) y 9/8 = 2(x 3/4) 2 y = 2(x 3/4) 2 9/8 The above equation represent the standard form of the equation of parabola The standard form of the parabola with vertex (h, k) and axis of symmetry x = h is y = a(x h) 2 k The vertex form of the equation of parabola is y = 2(x 3/4) 2 9/8 and Vertex (h




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To Convert from f (x) = ax 2 bx c Form to Vertex Form Method 1 Completing the Square To convert a quadratic from y = ax 2 bx c form to vertex form, y = a(x h) 2 k, you use the process of completing the square Let's see an example Convert y = 2x 2 4x 5 into vertex form, and state the vertex While the standard quadratic form is a x 2 b x c = y, the vertex form of a quadratic equation is y = a ( x − h) 2 k In both forms, y is the y coordinate, x is the x coordinate, and a is the constant that tells you whether the36 is the value for 'c' that we found to make the right hand side a perfect square trinomial;




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