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[最も共有された! √] y=x^2 2x-8 in vertex form 304863

 Suppose a parabola has a vertex (4,7) and also passes through the point (3,8) Write the equation of the parabola in vertex form f(x)=a(xh)^2k I believe h=4 k=7 Not sure what to do from here MathFrom this chart, we see that the parabola y = x 2 contains the points (3, 9) and (4, 16) On the other hand, he parabola y = 2x 2 contains the points (3, 18) and (4, 32) On the first equation, y = x 2, to move horizontally across the xaxis from x = 3 to x = 4, we move up vertically on the yaxis from y = 9 to y = 16 which is 7 unitsSo, to go from the point (3, 9) to (4, 16), we move over 1See the answer See the answer See the answer done loading

How Do I Convert The Equation F X X 2 2x 3 To Vertex Form Socratic

How Do I Convert The Equation F X X 2 2x 3 To Vertex Form Socratic

Y=x^2 2x-8 in vertex form

[最も選択された] 2x y=6 2x-y 2=0 340889-2x+y=6 2x-y+2=0

The graphical representation of the linear equation y5=0 is ( a point, a line, a curve)View Full Answer About Us;This solution is from chapter Pair of linear equations in two variables of class 10 In this solution graph was drawn and also find the area between two line

Ex 3 A Q15 X 2y 2 0 2x Y 6 0 Solve Each Of The Following Given Systems Of

Ex 3 A Q15 X 2y 2 0 2x Y 6 0 Solve Each Of The Following Given Systems Of

2x+y=6 2x-y+2=0

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